5(3y+7y^2)-y(7y+15)=28y^2

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Solution for 5(3y+7y^2)-y(7y+15)=28y^2 equation: 



5(3y+7y^2)-y(7y+15)=28y^2

We move all terms to the left:

5(3y+7y^2)-y(7y+15)-(28y^2)=0

determiningTheFunctionDomain
5(3y+7y^2)-28y^2-y(7y+15)=0

We add all the numbers together, and all the variables

-28y^2+5(3y+7y^2)-y(7y+15)=0

We multiply parentheses

-28y^2+35y^2-7y^2+15y-15y=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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